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CGP EDU Academic Team
Published on: September 12, 2026
A wooden block of volume 1000 cm 3 is suspended from a spring balance. It weighs 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of the spring balance is
Text Solution
Verified by ExpertsThe correct answer is:
D
Reading of the spring balance
= Apparent weight of the block
= Actual weight – upthrust
$= 12 - V_{in} \sigma g$
$= 12 - 500 \times 10^{-6} \times 10^{3} \times 10 = 12 - 5 = 7 \mathrm{N}.$
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